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How many terms..
How many terms will be there in the expression.. and which of these will be the highest one..
[(x-a)(x-b)(x-c)...... (x-z)](234x-535y)^23
This should be fairly easy if you are good in maths...
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Comments
sleepless in doha said
try #1: no. of terms is ... ...27 terms x 24 terms = 648
highest term is [(234)^23]*x^49
jilfer said
sorry sleepless... ...Do try again...
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shreeya said
Jilfer... ...Next term is ZERO...am I right?
[(x-a)(x-b)(x-c)...... (x-z)](234x-535y)^23
=<(x-a)(x-b)......(x-y)(x-z)> (234x-535y)..23
=(0)(234x-535y)..23
=0
shreeya said
Ohh missed a term there ...Ohh missed a term there (x-x), that will make everything ZERO.. I think I am doing it right?
shreeya said
Jllfer....am I right ...Jllfer....am I right there?
jilfer said
Shreeya...you are ...Shreeya...you are right..Since (x-x)comes in the equation, answer is 0..
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sleepless in doha said
missed that x-x ...:)